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D( a )
a < 0
a < 0
a in <0:+oo)
a^(5/6)*(a^(6/5)+a^(3/5)) = 0
a^(6/5)+a^(3/5) = 0
a^(3/5)*(a^(3/5)+1) = 0
1*a^(3/5) = -1 // : 1
a^(3/5) = -1
( -1 < 0 i 3/5 in (0:1) ) => a naleu017Cy do O
a^(3/5) = 0
a^(3/5)*a^(5/6) = 0
( a^(3/5) )
1*a^(3/5) = 0 // : 1
a^(3/5) = 0
a = 0
( a^(5/6) )
1*a^(5/6) = 0 // : 1
a^(5/6) = 0
a = 0
a in { 0, 0 }
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